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    Electric field and bounded charges on dielectric surfaces.

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    A uniformly charged straight wire of radius a carries linear charge density( lambda). The wire is coated with a linear dielectric material of susceptibility and external radius b.

    a. Find electric field everywhere
    b. Find the volume and surface bound charge densities

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    Solution Preview

    Please see the attached file.

    A uniformly charged straight wire of radius a carries linear charge density( lambda). The wire is coated with a linear dielectric mateeerial of susceptibility and external radius b.

    a. find electric field everywhere
    b. Find the volume and surface bound charge densities

    (The straight wire of radius a must be a conducting one as the linear charge density is given)

    According to Gauss law the electric flux through a closed surface is where qi is the charge enclosed within the closed surface. The field strength at a point in the field is the flux per unit area normal to the surface.

    The mathematical form of gauss theorem is given as

    As we know that the charge remains on the outer surface of a conductor if we consider a cylindrical surface of radius r coaxial to the wire, such ...

    Solution Summary

    The solution gives electric field everywhere and the densities of the bound charges on the cylindrical dielectric layer on the long cylindrical wire having a liner charge density.

    $2.49

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