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A plastic sheet of thickness t has a uniform free chargedensity, +, embedded inside, and also one surface has a surface charge of -. Find the electric field and the potential as functions of distance from one surface. [Please neglect the issues of dielectric polarizability, the plastic simply functions to fix the charges in place].

where Q is the charge enclosed by the surface you integrate over, dO is an area element that has the direction of the outward normal.

In this problem you assume that the sheet is infinite, so the electric field is constant parallel to the sheet. Also the electric field only has a component orthogonal to the sheet. Let's denote the coordinate orthogonal to the plates as x. Put the plate with zero surface charge density at x = 0 and the plate with charge density sigma at x = t.

Let's first calculate the electric field outside the plastic medium. Apply Gauss's law to a box ...

Solution Summary

The electric field for charge density is determined.

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... The field due to each of these spherical charge distributions can be found from Gauss ... The net electric field is then the superposition of these two fields. ...

... Find the magnitude of the electric field at a point 1.5 ... We are asked to find the electric fields inside, on and ... 12) = 1.25 x 103 N/C Here ρ = charge density. ...

Given the uniform charge density on two parallel sheets, find the magnitude of the net electric field. Two very large parallel sheets are 5.00 cm apart. ...

... at r=R c) Use Gauss' Law to find the electric field inside and ... E, D, and P to find the electric fields without using ... Thus, the bound surface charge density is: ...

A uniformly charged disk of radius 35.0 cm carries charge with a density of 7.90 x 10^-3 C/m^2. Calculate the electric field on the axis of the disk at (a) 5.0 ...

... As the electric field lines originate on the plane charge and proceed on both the sides parallel to it, the line density on both the sides is same. ...

... with a line charge density of -2 uC/m, such that the two squares share the same center. This outer square has sides of 4m. What is the electric field at the ...