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A plastic sheet of thickness t has a uniform free chargedensity, +, embedded inside, and also one surface has a surface charge of -. Find the electric field and the potential as functions of distance from one surface. [Please neglect the issues of dielectric polarizability, the plastic simply functions to fix the charges in place].

where Q is the charge enclosed by the surface you integrate over, dO is an area element that has the direction of the outward normal.

In this problem you assume that the sheet is infinite, so the electric field is constant parallel to the sheet. Also the electric field only has a component orthogonal to the sheet. Let's denote the coordinate orthogonal to the plates as x. Put the plate with zero surface charge density at x = 0 and the plate with charge density sigma at x = t.

Let's first calculate the electric field outside the plastic medium. Apply Gauss's law to a box ...

Solution Summary

The electric field for charge density is determined.

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A uniformly charged disk of radius 35.0 cm carries charge with a density of 7.90 x 10^-3 C/m^2. Calculate the electric field on the axis of the disk at (a) 5.0 ...

... with a line charge density of -2 uC/m, such that the two squares share the same center. This outer square has sides of 4m. What is the electric field at the ...

... A solid, insulating sphere of radius a has a uniform charge density ρ and a total charge +Q. Find the magnitude of the electric field in the regions r<a and r ...

... outside both the rod and the shell to calculate the electric field outside the shell. A long straight conducting rod carries a linear charge density λ of +2.0 ...

... a) Determine the electric fields in the three regions r ... attached figure has been given an excess negative charge. ... What are the electric field strengths E1 to E3 ...

... 4.00 cm has a uniform volume charge density of 1.20 ... the same as before and the charge distribution is ... Therefore the electric field must be the same after this ...