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Rotational Equilibrium: Seesaw with Three Bodies

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On the seesaw shown to the right (see attachment), mass A is 60 kg. mass B is 30 kg, and mass C is 10 kg. Mass A is 1.0m from the pivot. Mass C is 3.0m from the pivot. The see saw is at an angle of 30 degrees from the horizontal. Calculate the torques of mass A and mass C about the pivot. Where you should place mass B in relation to the pivot for the system to be in rotational equilibrium. (I.e. there is no net torque on the system)?

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Solution Summary

The position of the third mass is determined for rotational equilibrium.

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Please see the attached.

The torque is the rotational effect of a force and is given by the product of force and the perpendicular distance of the line of action of the force from the axis of rotation called lever arm.
As the ...

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