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    Torque, Equilibrium, & Stability

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    Two children are sitting on a seesaw. If one child has a mass of (m1) =22.0 kg and sits 2.30 m from the center pivot:
    (a) How far from the pivot must the second child (m2) = 30.0 kg sit for them to balance?
    (b) What is the net upward force of the pivot on the seesaw? The seesaw has a uniform mass distribution of 25 kg.

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    Solution Preview

    (a) The child, 22 kg, sitting to the left of the seesaw gives a counterclockwise torque; whereas the child, 30 kg, sitting to the ...

    Solution Summary

    The solution is answered with equations and brief explanations. How far the pivot must the second child be balanced is determined.