Two children are sitting on a seesaw. If one child has a mass of (m1) =22.0 kg and sits 2.30 m from the center pivot:
(a) How far from the pivot must the second child (m2) = 30.0 kg sit for them to balance?
(b) What is the net upward force of the pivot on the seesaw? The seesaw has a uniform mass distribution of 25 kg.
(a) The child, 22 kg, sitting to the left of the seesaw gives a counterclockwise torque; whereas the child, 30 kg, sitting to the ...
The solution is answered with equations and brief explanations. How far the pivot must the second child be balanced is determined.