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current in a 48.1 mH inductor changes with time

The current in a 48.1 mH inductor changes with time as I = bt^2 - at. With a = 2.7 A/s and b = 3 A/s^2, find the magnitude of the induced emf at t = .992 s. Units of V

At what time is the emf zero? Units of s

Solution Preview

i = bt^2 - at = 3t^2 - 2.7t
<br>=> di/dt = 6t - 2.7
<br>induced emf ...

$2.19