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Finding rms current through Capacitor and Inductor

A circuit consists of a sine wave signal generator and a reactive component (L or C). The output of the generator is a sine wave with a peak amplitude of 8.8 volts at a frequency of 10.0 kHz.

a. The generator is connected to an inductor with L = 10.0 mH. What is the rms current flowing in the inductor?

b. The generator is connected to a capacitor with C = 0.0250 microF. What is the rms current flowing in the capacitor?

c. What is the power dissipated in the capacitor in part (b) above?

d. The inductor and capacitor in parts (a) and (b) above are connected in parallel. What is the resonant frequency of the parallel circuit?

Solution Preview

Given signal generator produces a sine wave of peak amplitude

V(peak) = 8.8 V, and frequency f = 10.0 kHz.

As it is a sine wave, the rms voltage can be deduced from (1) as

V(rms) = V(peak)/Sqrt(2) (1)

= 8.8/Sqrt(2)

= 6.2 V

a. Generator connected to an inductor (L = 10.0 mH). The impedance of a series inductor is given by (2) as

Z(L) = 2*pi*f*L (2)

Therefore impedance due to pure inductance (L ...

Solution Summary

Using knowledge of the driving voltage of a sine wave oscillator operating at 10 kHz the rms current through a parallel connected LC network is determined for each of the inductive and capacitive components. The resonant frequency of the LC network is also determined

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