5.) A square of paper measuring a on a side carries a total charge +q which is uniformly distributed over its surface. The square lies in the x-y plane with its center at the origin and its sides parallel to the coordinate axes. Find the electric field on any point on the y-axis with y > a. Show that this square looks like a point charge for the case y>> a.
9.) The electric charge of the proton is not concentrated at a point but rather distributed over a volume. According to experimental investigations at the Stanford Linear Accelerator, the charge distribution of the pro- ton can be approximated by an exponential function
p= ____ e^((-r)/b)
where r is the radial position inside the proton and b is a constant equal to 0.23 x 10^(-15)m. Find the electric field as a function of the radial distance. What is the magnitude of the electric field at r =1 x 10^(-15)m? Compare the electric field strength you find to that of a point charge of magnitude e. At what distances r do these two differ by 10% or more?© BrainMass Inc. brainmass.com October 10, 2019, 5:54 am ad1c9bdddf
See the attached file.
We begin by finding the field of a infinitely thin strip of charge (with linear charge density), of length 2L, parallel to the x axis at distance y off center.
Each such charge equals
Each of these charges contributes an electric field of:
Where and k is Coulomb constant
Due to symmetry, the horizontal contributions at point P from all these small charges will cancel itself and we are left with the vertical component:
Now we have to integrate all these contributions from to , but due to the parity of the integrand we need to integrate between to and multiply by 2:
To solve this integral we use the substitution:
Putting this together:
Hence the integral becomes trivial:
And its solution is:
If we use the identity (see appendix, equation 1.38)
This is the electric field of a single thin strip of charge of length 2L at distance y off its center.
Now we want to find the electric field along the y-axis, of a square plate of side length of 2L, centered about the origin, parallel ...
The solution finds the electric field on any point on a y-axis.