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    Electrostatics - Nonconducting Speheres

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    1. A nonconducting sphere has radius R=2.31cm and uniformly distributed charge q = +3.50fC. Take the electric potential at the sphere's center to be Vo = 0. What is V at radial distance (a) r =1.45cm and (b) r = R.
    ( answer is given as (a) is -0.268mV (b) -0.681mV, please show me the detail, thank you)

    2. Two particles, of charges Q1 and Q2, are separated by distance d horizontally. The net electric field due to the particles is zero at x = d/4. With V = 0 at infinity, locate (in terms of d) any point on the x axis (other than at infinity) at which the electric potential due to the two particles is zero.

    Thank you so much.

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    Solution Preview

    Please refer to attachment.

    Problem 1 : A non-conducting sphere has radius R=2.31cm and uniformly distributed charge q = +3.50 fC. Take the electric potential at the sphere's center to be Vo = 0. What is V at radial distance (a) r =1.45cm and (b) r = R.

    Solution :

    Q = 3.5 fC

    Gaussian surface r

    R=2.31cm

    Let us first derive a general expression for potential at any radius r.

    Let us consider a Gaussian surface of radius r (r < R) as shown in the fig.. Applying Gauss theorem we get :

    ∫E.ds = q/Є0 where E = Electric field intensity on ...

    Solution Summary

    Step by step solution provided for nonconducting spheres are examined. The electric potential due to the two particles in zero is analyzed.

    $2.49

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