Two positive charges, charge q0 are fixed on the x axis at positions +a and -a.

a) What is the Electric Field anywhere in the (x,y) plane, at position (x,y)? Be sure your answer clearly denotes the vector nature of the electric field.

c) A third charge, q3 , (mass m3 ) is at position (0, 0 y ). What is the force on this charge?

d) What is the minimum speed of the third particle at position (0, 0 y ) in order for it to
(i) reach the origin , (0,0)
(ii) move off to infinity (plus or minus).

Be sure to consider both signs of 3 q to answer these.
The answers may not algebraically reduce to 'nice' solutions in general. Be sure to present in terms of defined variables.

Solution Preview

Please view the attachment below for a complete solution.

A) According to Superposition law, the electric field due to some distribution of charges is equal to the sum of electric fields due to each of those charges. Taking that into account, we just have to find the field due to each of those q0 charges at position (x,y) and sum them to get the total electric field at (x,y). Electric field is a vector value, so we can write:

Etotal = E1 + E2,

Where E1 and E2 are fields due to charges at x=-a and x =a respectively. The E's are vector values.

Now we can write that vector equation in components on x and y axis:

Etotal x = E1 x + E2 x
Etotal y = E1 y + E2 y

B) We can use the ...

Solution Summary

This job embodies electric forces, field and potentials.

... It investigates the electric field, potential, and force of the point charge. 1.) One particle has a mass of 3.00 * 10-3 kg and a charge of +7.60 µC. ...

... 2) Find the electric field and potential at the point (0.0 ... all the charges are positive, the force is of ... arrows indicate the direction of the forces exerted on ...

... a: Calculate the size of the electric field at k ... b: Calculate the size of the force on a charge of 8.00 ... The electric potential due to a point charge is V = kQ/r ...

... a) Potential difference between two points is defined as the work ... charge placed at A will experience a force in the direction of the electric field ie -x ...

... Find the strength of the electric field to produce this force. Solution: ... Gravitational forces acts upon all the masses while electric forces act only ...

... 2. Points A and B have electric potentials of 332 V and ... B is minus the product of the electrostatic force on the charge due to the electric field and the ...

Electroatatics and Lighting force. ... A positive point charge will have positive (more then zero) potential energy only in an external electric field. ...

Electric potential and electric field of two ... a. Find the electric forces exerted on each other (magnitude and direction) b. Find the electric field from ...

...Electric field E = -dV/dl or dV = - Edl (2 ... dl = displacement and dV = change in potential for displacement ... the proton experiences a force of magnitude ...