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# change in electric potential energy

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1. A uniform electric field with a magnitude of 6050 N/C points in the positive x direction. Find the change in electric potential energy with a +12.5-µC charge is moved 5.50 cm in (a) the positive x direction (b) the negative x direction, and (c) in the positive y direction.

2. Points A and B have electric potentials of 332 V and 149 V, respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA. When the electron is released from rest at point B, however, its kinetic energy when its reaches point C is KB = 2 KA. What is (a) the electric potential at point C and (b) the kinetic energy KA?

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1. A uniform electric field with a magnitude of 6050 N/C points in the positive x direction. Find the change in electric potential energy with a +12.5-µC charge is moved 5.50 cm in (a) the positive x direction (b) the negative x direction, and (c) in the positive y direction.
Let us denote the initial and final positions of the charge A and B, respectively.
The change in the electric potential energy is equal to the work done to move the charge. The work ...

#### Solution Summary

The solution shows how to find out the change in electric potential energy of an uniform electric field.

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