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change in electric potential energy

1. A uniform electric field with a magnitude of 6050 N/C points in the positive x direction. Find the change in electric potential energy with a +12.5-µC charge is moved 5.50 cm in (a) the positive x direction (b) the negative x direction, and (c) in the positive y direction.

2. Points A and B have electric potentials of 332 V and 149 V, respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA. When the electron is released from rest at point B, however, its kinetic energy when its reaches point C is KB = 2 KA. What is (a) the electric potential at point C and (b) the kinetic energy KA?

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1. A uniform electric field with a magnitude of 6050 N/C points in the positive x direction. Find the change in electric potential energy with a +12.5-µC charge is moved 5.50 cm in (a) the positive x direction (b) the negative x direction, and (c) in the positive y direction.
Let us denote the initial and final positions of the charge A and B, respectively.
The change in the electric potential energy is equal to the work done to move the charge. The work ...

Solution Summary

The solution shows how to find out the change in electric potential energy of an uniform electric field.

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