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    Calculate net electric potentials due to 3 charges, ball w charge placed in field

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    Calculate net electric potentials due to 3 charges, ball w charge placed in field.

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    https://brainmass.com/physics/coulombs-law/calculate-net-electric-potentials-due-charges-ball-charge-placed-field-6887

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    Solution:

    q1 =1.1 μC
    q2 = -2 μC
    q3 = 1.1 μC
    Distance between two charges q1 and q3 can be calculated as
    q1 q3 distance = (0.25 + 0.25)1/2
    = 0.707 m
    So distance between q1 and A will be r1 = 0.707/2
    r1 = 0.353 m
    Distance between charge q2 and A will also be same as above (r2) = 0.353 m
    Distance between charge q3 and A will be r3 = 0.353 m
    Potential at point A due to Charge q1 = K*(q1/r1)
    Value of K is equal to 1/40
    where o is permittivity of free space .Its volume is 8.85 x 10-12 c2/Nm2.
    Thus in S.I. system numerical value of K is 8.98755 x 109 Nm2c-2.

    So V1 = 8.98755 * 109 *(1.1*10-6)/ (0.353)
    = 28.006*103 Volt
    Potential at point A due to Charge q2, V2= K*(q2/r2)
    = 8.98755 * 109 *(-2*10-6)/ (0.353)
    V2 = - 50.92*103 Volt

    Potential at point A due to Charge q3, V3 = K*(q3/r3)
    V3 = 8.98755 * 109 ...

    Solution Summary

    The expert calculates the net electric potentials due to three charges. A ball with a charge being placed in a field is determined. With careful explanations and complete formulas and calculations, the problem is solved.

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