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    System of Electric Charges

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    3) A particle carrying charge qA = -8 × 10^-4 C is placed at point A and a particle carrying charge qB = -2 × 10^-4 C is placed at point B.

    a) Find the magnitude and direction of the electric field at point C.
    b) Find the electric potential at point C.
    c) Find the direction and magnitude of the electrostatic force acting on the particle carrying charge qC = -3 × 10^-5 C placed at point C.
    d) How much work would one need to do to move particle qC from its location at C to infinity?
    e) Is there a point along the line joining charges qA and qB where if you placed charge qC it will experience no acceleration? If so, where? Specify the distance to qA.

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    Solution Preview

    Please refer to the attachment.

    C D

    A 2m 4m B

    x 6-x

    qA = -8 x 10-4 C
    qB = -2 x 10-4 C
    qC = -3 x 10-5 C

    a) Magnitude of electric field at C due to qA = EA = (1/4Πε0)qA/rAC2 = 9x109x(8 x 10-4)/22 = 18x105 N/C. Direction of EA is towards left because a unit +ve charge placed at C will be attracted by charge at A ...

    Solution Summary

    Step-by-step solution is provided determining the electric field, potential etc. due to a system of charges.