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Electric Potential and Electric Potential Energy

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A point charge of -6.8 µC is at the origin.
(a) What is the electric potential due to this charge at (-2.0 m, 0)?

(b) What is the electric potential to this charge at (2.0 m, -2 m)?

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The potential of a point charge q at distance r from it is

V = q/(4*pi*epsilon0*r)

where epsilon0 = 8.85 x 10^{-12} C^2 /(N*m^2) is the permitivity of ...

$2.19
See Also This Related BrainMass Solution

change in electric potential energy

1. A uniform electric field with a magnitude of 6050 N/C points in the positive x direction. Find the change in electric potential energy with a +12.5-µC charge is moved 5.50 cm in (a) the positive x direction (b) the negative x direction, and (c) in the positive y direction.

2. Points A and B have electric potentials of 332 V and 149 V, respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA. When the electron is released from rest at point B, however, its kinetic energy when its reaches point C is KB = 2 KA. What is (a) the electric potential at point C and (b) the kinetic energy KA?

See attached file for full problem description.

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