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# Electric Fieldss

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A 43.2 nC Charge is located at position (x,y) = (1.0 cm, 2.0 cm). At what position (x,y) position is the electric field

1) At -225,000i N/C?
2) At (161,000i + 80,500j) N/C
X=?
Y=?
3) At (21,000i - 28,800j) N/C
X=?
Y=?

https://brainmass.com/physics/electric-magnetic-fields/electric-fieldss-146984

#### Solution Preview

The absolute value of the electric field is

E = kq/&#916;r^2, (1)

where k = 8.988×10^9 N m^2 C^{&#8722;2}, the charge is given as q = 43.2×10^{-9} C, and &#916;r is the distance from the charge (NOT from the origin).

The absolute values of the electric field in the 3 cases given are

E_1 = 225,000 N/C,

E_2 = sqrt(161,000^2 + 80,500^2) &#8776; 180,000 N/C,

E_3 = sqrt(21,000^2 + 28,800^2) &#8776; 35,643 N/C.

From equation (1) we have

&#916;r ...

#### Solution Summary

A 43.2 nC Charge is located at position (x,y) = (1.0 cm, 2.0 cm). At what position (x,y) position is the electric field

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