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Drawing and Computing Electric Field

Please assist me with the attached electric field [map] problem.



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8.6) part a is done at the end.

b) EI*4pi*r^2 = Q/eps
=> EI = Q/(4pi*eps*r^2) (radially outward) --Answer

c.) EII*4pi*r^2 = (Q-2Q)/eps
=> EII = Q/(4pi*eps*r^2) (radially inward) --Answer

d.) Because, the charge in the inside region will be = Q - 2Q = -Q
Therefore the charge ...

Solution Summary

This solution demonstrates how to solve equations for electric field, as well as includes an attached .jpg file with a diagram of electric field and induced charge.