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    Range Difference and Radar Problem

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    See the attached files.
    Part a of the problem - word document - requires determination of the range at point C and P then determining the difference.

    I'm unsure if I need to concern myself with the Taylor series expansion of the range equation. In essence I opted to determine theta then solve for R using the range equation (right before the Taylor expansion) found in the latter part of page 2.

    In determining the Doppler I tried to use the first term of the doppler equation. See 'word document' for equation that's missing in the PDF.

    My approach could be wrong hence, ...

    For a description of synthetic aperture radar see:
    http://www.sandia.gov/radar/whatis.html.

    © BrainMass Inc. brainmass.com March 4, 2021, 6:06 pm ad1c9bdddf
    https://brainmass.com/physics/doppler-shift/range-difference-radar-problem-29259

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    earth equator velocity Ve = 463 m/s = 0.463 km/s

    Because, for stationary earth range,
    R = sqrt(xo^2 + (yo-V*t)^2 + h^2)

    For rotating earth,
    R = sqrt((xo - Ve*t)^2 + (yo-V*t)^2 + h^2)

    xo = 300 km
    h = 800 km
    L = 15 km
    V = 7.6 km/s
    Assume at t =0: yo = 0 (theta_o = 90 degree)

    => T = L/V = 15/7.6 = 1.97368 s
    => T/2 = 0.98684 s

    Therefore,
    -0.98684 <= t <= ...

    Solution Summary

    The solution provides step by step calculations for questions with regards to a synthetic aperture radar. The solution involves calculations of range difference at the two edges of a synthetic aperture and the Doppler ship at the center of the synthetic aperture.

    $2.19

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