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    How fast must a 10.5g bullet be traveling when it strikes a ballistic pendulum that consist of a block of wood of mass 3.0kg that is suspended by a cord? The bullet gets embedded in the block. The block rises by .22m after the impact.

    a. 143 m/s
    b. 595 m/s/s
    c. 595 m/s
    d. 2.67 m/s

    © BrainMass Inc. brainmass.com September 28, 2022, 3:17 am ad1c9bdddf
    https://brainmass.com/physics/conservation-of-momentum/solving-conservation-momentum-problem-38163

    SOLUTION This solution is FREE courtesy of BrainMass!

    Answer: c. 595 m/s
    From the conservation of momentum
    mv = (m+M) V

    m= mass of bullet= 10.5 g= 0.0105 Kg
    M= mass of wood= 3 Kg
    (m+M)= 3.0105 Kg

    But V= square root of (2gh)
    g= 9.81 m/s^2
    h= 0.22 m

    Therefore V= 2.08 m/s

    mv = (m+M) V
    or v= (m+M) V/ m= 596 m/s

    Answer: 596 m/s

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com September 28, 2022, 3:17 am ad1c9bdddf>
    https://brainmass.com/physics/conservation-of-momentum/solving-conservation-momentum-problem-38163

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