Purchase Solution

Impulse Momentum, Conservation of Linear Momentum, & Collisions

Not what you're looking for?

Ask Custom Question

See attached file.

The problems came out from Physics 7th edition by Cutnell and Johnson, chapter 7. The sections include 1) the impulse-- momentum theorem 2) the principle of conservation of linear momentum 3) collisions in one dimension 4) collisions in two dimensions and 5) center of mass.

Purchase this Solution

Solution Summary

Impulse momentum, conservation of linear momentum and collisions are examined in the solution.

Solution Preview

**Please consider significant figures and if possible, draw visual graphics**
(The Impulse Momentum)
 A golfer, driving a golf ball off the tee, gives the ball a velocity of +38 m/s. The mass of the ball is 0.045 kg, and duration of the impact with the golf club is 3.0 x 10-3 s. (a) what is the change in the momentum of the ball by the club.

Solution: Initial momentum of the ball = mvi = 0.045 x 0 = 0

Final momentum of the ball = mvf = 0.045 x 38 = 1.71 kg.m/s

 A volleyball is spiked so that its incoming velocity of +4.0 m/s is changed to an outgoing of -21 m/s. The mass of the volleyball is 0.35 kg. What impulse does the player apply to the ball?

Solution: Momentum of the incoming ball = mv = 0.35 x 4 = + 1.4 kg.m/s

Momentum of the outgoing ball = - 0.35 x 21 = - 7.35 kg.m/s

Impulse = Change in momentum = - 7.35 - 1.4 = - 8.75 kg.m/s
(The Principle of Conservation of Linear Momentum)

 A 5.5-kg swimmer is standing on a stationary 210 kg floating raft. The swimmer then runs off the raft horizontally with a velocity of +4.6 m/s relative to the shore. Find the recoil velocity that the raft would have if there were no friction and resistance due to the water.

Solution:: Initial momentum of the swimmer = Initial momentum of the raft = 0

Final momentum of the swimmer (at the instant he runs off the raft) = mv = 55 x 4.6 = 253 kg.m/s [mass of the swimmer as stated in the problem 5.5 kg which obviously is a typographical error. The mass has been assumed as 55 kg]

Let the recoil velocity of the raft be v. Then, final momentum of the raft (at the instant the swimmer runs off the raft) = 210v. By conservation of linear momentum we have:

Sum of the momentums of the swimmer and the raft at the instant the swimmer jumps off the raft = Sum of the momentums of the swimmer and the raft before the swimmer jumps off the raft

253 + 210v = 0 o v = - 1.2 m/s

Raft will move backwards at 1.2 m/s
(Collisions in One Dimension and Collisions in Two Dimensions)

 Kevin has a mass of 87 kg and skating with in-line skates. He sees his 22-kg younger brother up ahead standing on the sidewalk, with his back turned. Coming up from behind, he grabs his brother and rolls off at a speed of 2.4 m/s. Ignoring friction, find Kevin's speed just before he grabbed his brother.

Solution: Let initial speed of Kevin be v. Initial speed of brother is zero. Final speed of both together is 2.4 m/s.

Final momentum of Kevin & brother = Initial momentum of Kevin + Initial momentum of brother

(87 + 22) x ...

Purchase this Solution

Free BrainMass Quizzes
Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.

The Moon

Test your knowledge of moon phases and movement.

Basic Physics

This quiz will test your knowledge about basic Physics.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.