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Collision of a car: Speed, average force, total momentum

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A car with a mass of 2200 kgm traveling at a velocity of 20 m/sec collides with a parked car. After the collision its velocity is +10 m/sec. If the mass of the parked car is 1200 kgm, determine

(a) Speed of the parked car after the collision.
(b) Average force exerted on the parked car if the collision time (delta t) =0.1 sec.
(c) Total momentum after collision.

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Solution Summary

The solution explains and shows all the formulas used to solve the problem. The speed of the parked car after the collision, the average force exerted on the parked car if the collision time and the total momentum after collision is calculated.

Solution provided by:
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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
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