A 0.1-kg steel ball is dropped straight down onto a hard horizontal floor and bounces straight up. Its speed just before "and just after " with the floor is 10m/s.

Determine the magnitude of impulse delivered to the floor by the steel ball.

Question #3
A 0.50kg-bomb is sliding along an icy pond (frictionless surface) with a velocity of 2.0 m/s to the west. The bomb explodes into two pieces. After the explosion, a 0.20-kg piece moves south at 4 m/s.

What are the components of the velocity of the 0.30-kg piece?

Question #4
Two cars of equal mass collide on a horizontal frictionless surface. Before the collision, Car A is at rest while Car B has a constant velocity of 12m/s. After the collision, the two bodies are stuck together

What is the speed of the composite body (A+B) after the collision?

Question #5

The head of a hammer (m=1.5kg) moving at 4.5 m/s strikes a nail and bounces back with the same speed after an elastic collision lasting 0.075 s.

What is the magnitude of the average force the hammer exerts on the nail?

Solution Summary

The impulse and momentum related questions are investigated. Also, it explains how to solve collision by applying conservation of momentum. The solution is detailed and well presented.

... Hence, sum of the linear momentums of the pieces ... be same as the linear momentum of the ...Impulse momentum, conservation of linear momentum and collisions are ...

... Sum of the momentums of the three pieces after breakup = Momentum of the spaceship ... Friction force, impulse momentum, mass and speed and directions are examined ...

... By impulse-momentum theorem: Change in momentum of the bullet ... c) By the law of conservation of linear momentum: Sum of momentums of the individual with gun and ...

Impulse, momentum conservation, potential energy. 1. Define the term impulse. ...Impulse, momentum conservation, potential energy and forms of energy is examined. ...

Impulse and Momentum. See attached file for full problem description. ...Impulse and Momentum are investigated. The solution is detailed and well presented. ...

... p = F ∆t = −8397 N × 0.272 s = −2284 Ns Therefore, the momentum change of the ... What was the magnitude of the impulse (in Ns) imparted to the boulder? ...