While being thrown, a net force of 132 N acts on a baseball (mass = 140 g) for a period of 4.5 X 10^-2 seconds.
The balls initial velocity is zero before leaving the pitchers hand.
When the batter hits the ball, a net force of 1320 N, opposite the direciton of the balls initial motion, acts on the ball for 9 X 10^-3 seconds during hte hit.
What is the velocity of the ball after it is a)thrown b) hit back.
We know that Impulse = change in momentum = mass * dV
<br>Also impulse = force * time
<br>(Let the force act in the +ve x direction)
<br>From data, Impulse = 132N * 4.5* 10^-2 second = 5.94 N Sec
<br>This impulse would cause a momentum change of 5.94 kg*m/s
<br>Thus a) change in momentum = +5.94 Kg m/s ...
Solution is given with all required mathematical steps.