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Physics - Potential Energy & Conservation

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A 60 kg trampoline artist jumps vertically upward from the top of a platform with a speed of 4.5 m/s.
(a) How fast is he going as he lands on the trampoline, 3.0 m below?
1 ......m/s
(b) If the trampoline behaves like a spring of spring constant 5.2 104 N/m, how far does he depress it?
2 .......m

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Solution Summary

The potential energy and conservation in a platform are examined. A complete, neat and step-by-step solution is provided.

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(1) Upward motion:

u = 4.5 m/s, a = -9.8 m/s^2, v = 0

s = (v^2 - u^2)/2a = (0 - 4.5^2) / 2(-9.8) = 1.033 m

Downward motion:

u = 0, s = 3 + ...

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