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Conservation of Momentum and Energy

Problem: m1 starts from rest at height h. At the bottom of the frictionless slope stands mass m2. m1 is then let go, and collides with m2 an elastic collision. What will be the final height m1 will attain after recoiling from m2?

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Problem: m1 starts from rest at height h. At the bottom of the frictionless slope stands mass m2. m1 is then let go, and hits m2 an elastic collision. What will be the final height m1 will attain after recoiling from m2?

Here is the path to solution;

1. m1 has initial potential energy. At the bottom of the slope, all this potential energy is converted to kinetic energy. From this we can find the block's velocity just before the collision.

2. During the collision there is a momentum transfer event. The collision is elastic, since we know that the blocks don't stay together, and therefore energy must be conserved as well. If the collision were inelastic, energy would not be conserved. So from conservation of ...

Solution Summary

A step by step solution of the problem, utilizing the laws of energy and momentum conservation.

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