Determine magnitude of the centripetal force that acts on a skater in 'crack the whip'
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In a skating stunt known as "crack-the-whip," a number of skaters hold hands and form a straight line. They try to skate so that the line rotates about the skater at one end, who acts as the pivot. The skater farthest out has a mass of 80.0 kg and is 6.10 m from the pivot. He is skating at a speed of 6.80 m/s. Determine the magnitude of the centripetal force that acts on him.
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Centripetal force = m*v^2/r
here,
m = mass = 80.0 kg
r = radius of the circluar ...
Solution Summary
With explanations and formulas, the problem is solved.
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