# Angular Momentum and Centripetal Force

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A car of mass 1000kg moves with a speed of 50 m/s on a circular track of radius 100m. What is the magnitude of its angular momentum (in kg.m^2/s) relative to the center of the racetrack?

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Answers:

a) 5 x 10^2

b) 5 x 10^6

c) 2.5 x 10^6

d) 2.5 x 10^4

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A 50 kg ice skater is moving at 5 m/s when she grabs the loose end of a rope, then opposite end of which is tied to a pole. She then moves in a circle of radius 1m around the pole. Determine the force exerted by the rope on her arms.

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a) 1250 N

b) 250 N

c) 50 N

d) 1100 N

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##### Solution Summary

The solution provides calculations for angular momentum and centripetal force. Step by step problem solving and equations are provided.

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Hello and thank you for posting your question to Brainmass.

Angular momentum is defined as

J=P*r*sin(w)

Where P is the linear momentum vector's magnitude of the object and r is the distance vector's magnitude from the object to the ref. point. w is the angle between the two vectors.

in our case ...

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