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    Circular motion

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    A car crests a hill at an extreme velocity and "gets air". Explain the physics of why this is.

    © BrainMass Inc. brainmass.com October 4, 2022, 4:24 pm ad1c9bdddf
    https://brainmass.com/physics/circular-motion/car-circular-motion-126692

    SOLUTION This solution is FREE courtesy of BrainMass!

    When an object executes a circular path it needs a "cenripetal force" for doing so. This force acts on the object towards the centre of the circular path. In absence of such a force the object will not move on the circular path and will instead proceed along a straight line tangentially to the circular path. The magnitude of the centripetal force (F) required for an object of mass m, to move on a circular path of radius r with a speed v is given by : F = mv^2/r .......(1)

    From (1) it is clear that higher the speed, larger the centripetal force required.

    As the car crests a hill, at the top of the hill, the car will be moving on a curved path and will therefore need centripetal force which is provided by the gravitational force (i.e. weight) which acts downwards i.e. towards the centre of curvature of the curved path at the hill top. At slow speeds, the requirement of centripetal force is also lesser and the weight of the car may be able to provide the same. The car will successfully crest the hill. However, at very high speeds, the weight of the car will not be able to provide the required centripetal force and the car instead of following the contour of the hill will "take off" at a tangent and will be in the air before crashing into the valley.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com October 4, 2022, 4:24 pm ad1c9bdddf>
    https://brainmass.com/physics/circular-motion/car-circular-motion-126692

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