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    Maxwell Boltzmann translational energy distribution.

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    What is the Maxwell Boltzmann translational energy distribution in units of k T

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    https://brainmass.com/physics/boltzmann-distribution/maxwell-boltzmann-translational-energy-distribution-30166

    Solution Preview

    The Maxwell Boltzmann speed distribution, P(v), is given by:

    P(v) = 4 pi (m/(2 pi k T))^(3/2) Exp[-m v^2/(2 k T)] v^2

    P(v)dv is the probability that a molecule of mass m has a speed between v and v + dv. Let's denote the energy distribution by Q(E). Then Q(E)dE is the probability that a molecule has an energy between E and E + dE. To find Q(E), eliminate v in P(v)dv ...

    Solution Summary

    The formula of the Maxwell Boltzmann translational energy distribution is derived.

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