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Momentum, Impulse, and Collisions

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Starting at t= 0, a horizontal net force F = (0.280 N/s)ti + (-0.450 N/s^2)t^2j is applied to a box that has an initial momentum p= (-3.00 kg.m/s)i + (4.00 kg.m/s)j. What is the momentum of the box at t= 2.00s?

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The expert examines momentum, impulses and collisions for the horizontal net forces.

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Force F = 0.28 ti + (-0.45)t^2j
Initial momentum (@ t = 0) p_initial = 3.00i + 4.00j
Final momentum (@ t = 2.00 sec) ...

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  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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