Angular Velocity of a Block on a Heated Spinning Rod

A 1.10 m-long massless rod is pivoted at one end and swings around in a circle on a frictionless table. A block with a hole through the center can slide in and out along the rod. Initially, a small piece of wax holds the block 10.0 cm from the pivot. The block is spun at 50.0 rpm, then the temperature of the rod is slowly increased. When the wax melts, the block slides out to the end of the rod. What is the final angular velocity? Give your answer in rpm.

Solution Preview

By the law of the conservation of angular momentum;
m*r1^2*w1 = ...

Solution Summary

The solution includes a quick, simple answer to finding the angular velocity in question, drawing on relevant theory and formulae and explaining exactly where each number used comes from.

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Please see attached.
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