A sample of ideal gas is expanded to twice it original volume of 1.00m^3 in a quasi-static process for which P = alpha*V^2, with alpha = 5.00atm/m^6. How much work is done on the expanded gas?
I know that work is the integral of - PdV but I can't seem to get the right answer. Can you help?© BrainMass Inc. brainmass.com July 18, 2018, 3:20 am ad1c9bdddf
P = alpha V ^2
Work done = integral of P dV = integral of alpha V ^2 dV = alpha x ...
The solution calculates work done on the expanded gas.