A sample of ideal gas is expanded to twice it original volume of 1.00m^3 in a quasi-static process for which P = alpha*V^2, with alpha = 5.00atm/m^6. How much work is done on the expanded gas?
I know that work is the integral of - PdV but I can't seem to get the right answer. Can you help?
Solution Preview
P = alpha V ^2
Work done = integral of P dV = integral of alpha V ^2 dV = alpha x ...
Solution Summary
The solution calculates work done on the expanded gas.
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