I know that work is the integral of - PdV but I can't seem to get the right answer. Can you help?© BrainMass Inc. brainmass.com October 24, 2018, 6:12 pm ad1c9bdddf
P = alpha V ^2
Work done = integral of P dV = integral of alpha V ^2 dV = alpha x ...
The solution calculates work done on the expanded gas.
Thermodynamic of cyclic process of an ideal gas
An ideal gas described by T(initial)=300K,P(initial)=1 bar and V(i)=10 L is heated at constant volume until P=10 bar.It then undergoes a reversible isothermal expansion until P=1bar.It is then restored to its original state by the extraction of heat at constant pressure. Calculate w for each step.View Full Posting Details