## The First Six Books: Together with the Eleventh and Twelfth |

### Inni boken

Resultat 1-5 av 100

Side 14

“ If a straight line meets two straight lines , so as to make the “ two interior angles on the same side of it taken together “

“ If a straight line meets two straight lines , so as to make the “ two interior angles on the same side of it taken together “

**less**than two right angles , these straight lines being con“ tinually produced , shall at length meet upon ... Side 16

ROM the greater of two given straight lines to cut off a part equal to the

ROM the greater of two given straight lines to cut off a part equal to the

**less**. Let AB and C be the two given straight lines , whereof AB is the greater . It is required to cut off from AB , the greater , a part equal to C the**less**. Side 19

I. qual to AC , the

I. qual to AC , the

**less**, and join DC ; therefore , because in the triangles DBC , ACB , A DB is equal to AC , and BC common to D both , the two sides DB , BC are equal to the two AC , CB , each to each ; and the angle DBC is equal to ... Side 26

A NY two angles of a triangle are together

A NY two angles of a triangle are together

**less**than two right angles . А Let ABC be any triangle ; any two of its angles together are**less**than two right angles . Produce BC to D ; and because ACD is the exterior angle of the triangle ... Side 27

In like manner , it may demonstrated , that BAC , ACB , as also CAB , ABC are

In like manner , it may demonstrated , that BAC , ACB , as also CAB , ABC are

**less**than two right angles . Therefore any two angles , & c . Q. E. D. be PRO P. XVIII . THEOR . There HE greater fide of every triangle is opposite to the ...### Hva folk mener - Skriv en omtale

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The First Six Books: Together with the Eleventh and Twelfth Euclid Ingen forhåndsvisning tilgjengelig - 2016 |

### Vanlige uttrykk og setninger

added alſo altitude angle ABC angle BAC baſe becauſe Book caſe centre circle circle ABCD circumference common cone cylinder definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides figure firſt folid fore four fourth given angle given in poſition given in ſpecies given magnitude given ratio given ſtraight line greater Greek half join leſs likewiſe magnitude manner meet muſt oppoſite parallel parallelogram perpendicular plane priſm produced prop proportionals propoſition pyramid reaſon rectangle rectangle contained rectilineal remaining right angles ſame ſecond ſegment ſhall ſides ſimilar ſolid ſphere ſquare ſquare of AC Take taken theſe third triangle ABC wherefore whole

### Populære avsnitt

Side 483 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.

Side 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Side 81 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...

Side 105 - DEF are likewise equal (13. i.) to two right angles ; therefore the angles AKB, AMB are equal to the angles DEG, DEF, of which AKB is equal to DEG ; wherefore the remaining angle AMB is equal to the remaining angle DEF.

Side 167 - AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off.

Side 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.

Side 62 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.

Side 112 - To describe an equilateral and equiangular pentagon about a given circle. • Let ABCDE be the given circle; it is required to describe an equilateral and equiangular pentagon about the circle ABCDE. Let the angles of a pentagon, inscribed in the circle...

Side 200 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...

Side 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.