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    Each square n*n region of an image yields a vector of length n^2 such that the components of the vector are the grey levels of the pixels in the square. Let u, v be the vectors obtained from two image patches, let a be the average of the entries in u, let b be the average of the entries in V and let e be the vector of length n^2 such that each entry of e is equal to 1. Show that

    (u-a e).(v-b v)=u.v - (n^2 a b)

    NOTE: The textbook is "Image Based Information Processing"

    © BrainMass Inc. brainmass.com December 15, 2022, 5:22 pm ad1c9bdddf
    https://brainmass.com/math/vector-calculus/image-based-information-processing-79839

    Solution Summary

    This is a problem regarding vectors and images.

    $2.49

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