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    equation of a plane in 3-D space

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    Find the equation of a plane through the origin and perpendicular to: x-y+z=5 and 2x+y-2z=7

    © BrainMass Inc. brainmass.com October 9, 2019, 7:55 pm ad1c9bdddf
    https://brainmass.com/math/vector-calculus/equation-of-a-plane-in-3-d-space-133358

    Solution Preview

    The normal vector of plane x - y +z = 5 is a = (1, -1, 1).
    The normal vector of plane 2x + y - 2z = 7 is b = (2, 1, -2).
    Let vector c be ...

    Solution Summary

    The solution shows the calculation of equation a plane in three dimensional spaces by finding its normal vector.

    $2.19