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equation of a plane in 3-D space

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Find the equation of a plane through the origin and perpendicular to: x-y+z=5 and 2x+y-2z=7

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Solution Summary

The solution shows the calculation of equation a plane in three dimensional spaces by finding its normal vector.

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The normal vector of plane x - y +z = 5 is a = (1, -1, 1).
The normal vector of plane 2x + y - 2z = 7 is b = (2, 1, -2).
Let vector c be ...

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