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    Real Analysis : Empty Set and Nested Interval Property

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    Prove that: Intersection to infinity for n=1 (sign of intersection with infinity on top and n=1 in the bottom) of (0,1/n)=empty.
    (Notice that this demonstrates that the interval in the Nested Interval Property must be closed for the conclusion of the theorm to hold.)

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    The nested sequence of open bounded intervals,

    (0,1), (0,1/2), ...

    Solution Summary

    A real analysis problem is solved.