Proof for Vectors
Prove for any two vectors |alpha > and |beta>,
Let a = alpha and b = beta
Prove for any two vectors |a> and |b>,
(<a|a>^(1/2) + <b|b>^1/2)^2 greater than or equal to (<a| + <b|)(|a> + |b>)
Use the Schwartz inequality.
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Solution Preview
(<a|a>^(1/2) + <b|b>^1/2)^2 = <a|a> + <b|b> + 2(<a|a>.<b|b>)^1/2 = <a|a> + <b|b> + 2 |a| .|b|
(<a| + ...
Solution Summary
Using Schwartz, inequality, a vector identity is proved in the solution.
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