Explore BrainMass

Explore BrainMass

    Proof for Vectors

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Prove for any two vectors |alpha > and |beta>,
    Let a = alpha and b = beta
    Prove for any two vectors |a> and |b>,

    (<a|a>^(1/2) + <b|b>^1/2)^2 greater than or equal to (<a| + <b|)(|a> + |b>)

    Use the Schwartz inequality.

    © BrainMass Inc. brainmass.com December 16, 2022, 10:36 am ad1c9bdddf

    Solution Preview

    (<a|a>^(1/2) + <b|b>^1/2)^2 = <a|a> + <b|b> + 2(<a|a>.<b|b>)^1/2 = <a|a> + <b|b> + 2 |a| .|b|

    (<a| + ...

    Solution Summary

    Using Schwartz, inequality, a vector identity is proved in the solution.