Probability and Z-Scores

Related BrainMass Solutions

• Finding probability and area under a distribution

  Find the area under the standard normal probability distribution between the following pairs of z- scores. A. Z= 0 and z= 3.00 B. z= 0 and z= 1.00 C. Z = 0 and z = 2.00 D. Z = 0 and z = 0.62 E. z = 0 and z = 0.39 1.

• Probability using normal distribution

  (h) below -0.1 Cumulative probability corresponding to Z= -0.1 is 46.02% Thus area to the left of z= -0.1 is 46.02% Answer: 46.02% 0r 0.4602 Calculates probabilities using z scores from a normal distribution.

• Probability of obtaining certain sample scores in a normal

  278879 Probability of obtaining certain sample scores in a normal population For a normal population with µ = 100 and σ = 20 find the following.

• Stanford-Binet IQ Test Scores: Distribution, z score, probability

  P(-1.5 <= z <= 1.5) = .8664 Part (d) P(X > 136) = P(z > (136-100)/16) = P(z > 2.25) = .0122 or 1.22% The expert examines the Standford-Binet IQ test scores for distribution, z scores and probability.

• Compute z-scores given populations and sample size

  309870 Compute z-scores given populations and sample size For a population with a mean of 60 and a standard deviation of 24, find the z-score corresponding to each of the following samples. a. M = 63 for a sample of n = 16 scores b.

• Probabilities using the Normal Distribution

  For example, the probability that z lies between a and b under the standard normal distribution is denoted P(a < z < b) and this probability is the same as the area under the curve between the z-scores, z1 = a and z2 = b.

• Z-score, Normal Probability & Percentiles

  a value of Z say K such that P (Z ≤ K) = 0.50 From standard normal tables, Z = 0 The solution provides step by step method for the calculation of z-score and probability using the Z score.

• Normal Distribution, Standard Normal Distribution, Probability

  Normal Distribution, Standard Normal Distribution, Probability, Bell Curve and z-Scores are investigated.

• Some questions on normal distribution

  Solution: P(56 ≤ X ≤ 60) = P(0.8 < z < 1.6) = P(z < 1.6) - P(z<0.8) =0.9452-0.7881 = 0.1571 Answer: 0.1571 b. Find the probability that her age will fall between 49 and 53 years.

• Standard Deviation of SAT Scores

  Thanks This solution shows step-by-step calculations to determine the probability of the z-score being 0.25 for SAT-I scores and other statistical measures.