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# Dart Board Probability

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Assume a dart board with 4 scoring areas worth 20 pts, 10 pts, 5 pts and zero pts.
Person A has the following likelihood with each dart:
20 pts - 50%
10 pts - 15%
5 pts - 15%
0 pts - 20%

Person B has the following likelihood per dart:
20 pts - 20%
10 pts - 20%
5 pts - 10%
0 pts - 50%

Question: If Player A gets to throw 2 darts and Player B gets to throw 5 darts, how do you calculate the probability of Player A or Player B getting the highest total score?

https://brainmass.com/math/probability/dart-board-probability-389739

## SOLUTION This solution is FREE courtesy of BrainMass!

To find the expected number of points for each throw for each person, multiply the probability times the number of points:

Person A: ((20(.5))+(10(.15))+(5(.15))+(0(.2)))=12.25
So if person A threw two darts, their expected number of points would be 24.5

Person B: ((20(.2)+(10(.2))+(5(.1))+(0(.5))=6.5
So if person B threw five darts, their expected number of points would be 32.5

So the probability that A would win would be 24.5/(24.5+32.5)=.43
Therefore the probability that B would win would be .57

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!