Explore BrainMass

Explore BrainMass

    Dart Board Probability

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Assume a dart board with 4 scoring areas worth 20 pts, 10 pts, 5 pts and zero pts.
    Person A has the following likelihood with each dart:
    20 pts - 50%
    10 pts - 15%
    5 pts - 15%
    0 pts - 20%

    Person B has the following likelihood per dart:
    20 pts - 20%
    10 pts - 20%
    5 pts - 10%
    0 pts - 50%

    Question: If Player A gets to throw 2 darts and Player B gets to throw 5 darts, how do you calculate the probability of Player A or Player B getting the highest total score?

    Thank you in advance

    © BrainMass Inc. brainmass.com December 24, 2021, 9:32 pm ad1c9bdddf
    https://brainmass.com/math/probability/dart-board-probability-389739

    SOLUTION This solution is FREE courtesy of BrainMass!

    To find the expected number of points for each throw for each person, multiply the probability times the number of points:

    Person A: ((20(.5))+(10(.15))+(5(.15))+(0(.2)))=12.25
    So if person A threw two darts, their expected number of points would be 24.5

    Person B: ((20(.2)+(10(.2))+(5(.1))+(0(.5))=6.5
    So if person B threw five darts, their expected number of points would be 32.5

    So the probability that A would win would be 24.5/(24.5+32.5)=.43
    Therefore the probability that B would win would be .57

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 9:32 pm ad1c9bdddf>
    https://brainmass.com/math/probability/dart-board-probability-389739

    Attachments

    ADVERTISEMENT