Working with conditional probability.
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There are 12 light bulbs, 5 of which are defective. All bulbs look alike and have an equal probability of being chosen. Three light bulbs are selected and placed on the table.
Find the probability that:
a) All three are defective.
b) Two are defective.
c) That none are defective.
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Solution Summary
The probability of picking defective light bulbs is calculated.
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Assuming no replacement
Let defective bulbs be D
non defective bulbs be ND
a) P(all 3 defective) = D x D x D
= ...
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