Combinations and Subsets : Probabilities
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A committee consists of 8 married couples. In how many ways can a subcommitee of 5 people be chosen so that at most one married couple belongs to the subcommittee?
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Solution Summary
Combinations and probabilities are investigated.
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The number of ways to choose the 5 people without any limitation is:
C(16,5) = 16!/5! = (16*15*14*13*12)/(5*4*3*2*1) = 4368
The number of ways to choose exactly 2 couples ...
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