Ordinary differential equations
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(d^2 * y)/(d * t^2) + 6 * (dy/dt) + 9y = 0
y(0) = 10, y'(0) = 0
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(d^2 * y)/(d * t^2) + 6 * (dy/dt) + 9y = 0
y(0) = 10, y'(0) = 0
The auxiliary equation is:
m^2 + 6m + 9 = 0
(m+3)^2 = ...
Solution Summary
This shows how to solve a given ordinary differential equation.
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