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# Ordinary differential equations

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(d^2 * y)/(d * t^2) + 6 * (dy/dt) + 9y = 0

y(0) = 10, y'(0) = 0

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##### Solution Summary

This shows how to solve a given ordinary differential equation.

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(d^2 * y)/(d * t^2) + 6 * (dy/dt) + 9y = 0

y(0) = 10, y'(0) = 0

The auxiliary equation is:

m^2 + 6m + 9 = 0

(m+3)^2 = ...

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