Explore BrainMass

Explore BrainMass

    Approximation of Integrals and Taylor Polynomials

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Given ( INTEGRAL ln square(x)dx, as x from n to n+1 ) = ( INTEGRAL ln square (n+x)dx, as x from 0 to 1 ) = ( INTEGRAL [[ln(n+x) - ln(x) + ln(n)]square] dx, as x from 0 to 1 ),

    (a) Verify that ( LIMIT (n/ln(n)) [INTEGRAL (ln square (x)dx) - (ln square (n))] as n approach to the infinity ) = 1

    (b) Compute LIMIT ((n square)/ln(n)) [ INTEGRAL ln square (x)dx - ln square (n) - ((ln(n))/n)]

    © BrainMass Inc. brainmass.com March 6, 2023, 1:16 pm ad1c9bdddf

    Solution Preview

    Please see the attached file for the full solution.

    Thanks for using BrainMass.

    Well, before starting to solve the problem, I should mention that there is some vagueness in the question. From the description of the problem, I have figured out that I would use Taylor polynomials to approximate the integral. We have this information:

    That I agree and there is no problem, but if you trust me, I will tell you that the following equation does not hold at all:

    Upon your request, I can show you why, but for the moment let's forget about it. Of course, it is likely that there has been a typo.

    Ok, it is possible, but time consuming to ...

    Solution Summary

    Taylor polynomials are used to define limits are given. The approximation of integrals and taylor polynomials are analyzed.