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    Probabilstic Dynamic Programming

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    A vendor sells sweatshirts at football games. They are equally likely (0.5,0.5) to sell 200 or 400 sweatshirts per game. Each order placed to the supplier costs $500 plus $5 per quantity ordered. The vendor sells each sweatshirt for $8. The is a holding cost of $2 (inventory costs) for each shirt leftover after each game. The maximum inventory that the vendor can store is 400. The number of shirts that can be ordered from the supplier must be a multiple of 100. Determine an ordering policy that maximizes expected profits earned during the first three games of the season. Assume that any leftover sweatshirts have a value of $6.

    Here is where I started:

    State 1 = Game 3
    State 2 = Game 2
    State 3 = Game 1

    Decisions:
    Buy 100
    Buy 200
    Buy 300
    Buy 400

    I- inventory at beginning of each game

    Profits:=[(0.5*(200)*$8)-($500+($5*order))-($2*(order-200+I))]+ [(0.5*(400)*$8)-($500+($5*order))-($2*(order-400+I))]

    I am not sure I have the above formula correct?

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    https://brainmass.com/math/linear-programming/probabilstic-dynamic-programming-16744

    Solution Preview

    Please refer to the attachment.

    Your formula looks plausible. However, I noticed some minor mistakes.

    - It's impossible to order more than 400, because ...

    Solution Summary

    This solution discusses probabalistic dynamic programming.

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