Solving system of linear equations by elimination method
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2. the perimeter of a rectangle is 26m. the length is 1 m more than twice the width. Find the dimensions
What is the length? _____m what is the with?______m
4. Solve by the elimination method
x+5y=34
-x+9y=50
5.Solve by the elimination method
5x+5y= -13 -------------(1)
7x-3y= 19 -------------(2)
16. Solve by the elimination method
0.3x-0.2y=4
0.4x+0.3y= -------------- (2)
17) Solve by the elimination method
8x-9y=8.5 --------------- (1)
7y-2x=-4.5 ------------------------ (2)
18) Solve by the elimination method
0.05x+0.25y=66 ---------------- (1)
0.15x+0.05y=72 ---------------- (2)
19) the perimeter of a rectangle is 132 inches. The length exceeds the with by 34 minches. Find the length & Width
The length is ________ inc The Width is _________ inc.
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Solution Summary
This is a 3-page word document explaining in detail the solution process of a system of linear equations. Seven questions have been answered under this topic. Five of them are solved by the method of elimination. Word problems are solved by first constructing two linear equations and then solving them.
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(2)
Let the length be 'a' and width be 'b'.
Perimeter, 2(a+b) = 26 è
a + b = 13 ------------------------------- (1)
and length is 1 m more than twice the widthè
a = 1 + 2b ----------------------- (2)
Solve for a and b using (1) and (2):
a + b = 13 ------------------------------- (1)
a - 2b = 1 ----------------------- (2)
(1) - (2) è: 3b = 12 è b = 4
From (2), a = ...
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