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Solving a system of 3 linear equations.

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Question 1: Solve these linear equations for x, y, and z,
3x + 5y - 2x = 20
4x - 10y - z = -25
x + y - z = 5

the value of x is in the range
(1) -4 <= x <= -3
(2) -2 <= x <= 0
(3) 0 <= x <= 2
(4) 2 <= x <= 4

Note: "<=" means "less than or equal to"

Question 2: The value of y in Question 1 above lies in the range
(1) -4 <= y <= -2
(2) -2 <= y <= 0
(3) 0 <= y <= 2
(4) 2 <= y <= 4

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Solution Summary

Solving a system of 3 linear equations using substitution method.

Solution Preview

Question 1:
3x + 5y - 2z = 20
8x - 20y - 2z = -50
2x + 2y - 2z = 10
Now we subtract the third equation from the first two and ...

Solution provided by:
Chris Busu, PhD (IP)
Education
  • BSc, University of Bucharest
  • MSc, Ovidius
  • MSc, Stony Brook
  • PhD (IP), Stony Brook
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