# Surface area of a solid

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Identify the definite integral that represents the area of the surface formed by revolving the graph of f (x)= x^3 on the interval [0,1] about the y-axis.

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#### Solution Preview

Hi, here is the solution...

b

Area = ∫ [f(x)- g(x)]dx

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#### Solution Summary

This provides an example of finding the surface area of a solid of revolution.

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