Surface area of solid of revolution
Using the formula for the surface area of a revolving curve about the x-axis:
S=∫2πy√(1 + (dy/dx)²)dx throughout a,b
Find the area of the surface generated by revolving the curve about the x axis within the given boundaries
y=√(x + 1)
1≤x≤5
Please be detailed, showing the complete derivation, integration and substitution of limits to find the area.
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Solution Summary
This provides an example of finding the surface area of a solid of revolution.
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