# Surface area of solid of revolution

Using the formula for the surface area of a revolving curve about the x-axis:

S=∫2πy√(1 + (dy/dx)Â²)dx throughout a,b

Find the area of the surface generated by revolving the curve about the x axis within the given boundaries

y=√(x + 1)

1≤x≤5

Please be detailed, showing the complete derivation, integration and substitution of limits to find the area.

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#### Solution Summary

This provides an example of finding the surface area of a solid of revolution.

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