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    Revolutions of integrals - torus

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    The circle x=acost, y=asint, 0≦t≦2pi is revolved about the line x=b, 0<a<b, thus generating a torus (doughnut). Find its surface area.

    Area if the torus:_____________.

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    https://brainmass.com/math/integrals/revolutions-integrals-torus-22465

    Solution Preview

    Please see attached file

    A surface of revolution is formed by the rotation of a planar curve C about an axis in the plane of the curve and not cutting the curve. The Pappus--Guldinus theorem says that:
    • The area ...

    Solution Summary

    The area of the torus is found by revolutions of integrals.

    $2.49

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