# Integrals : Volume of Solid of Revolution

26. Let S be the closed region in the first quadrant of the xy-plane bounded by y = sin(pi x/2) and y = x for 0 ≤ x ≤ 1. What is the volume of the closed region in R3 obtained by revolving S about the x-axis?

A. 2 - (pi /2) B. pi /6 C. pi /3

D. pi /2 E. (2pi )/3

https://brainmass.com/math/integrals/integrals-volume-solid-revolution-33176

#### Solution Preview

Please refer to the attachment.

26. Let S be the closed region in the first quadrant of the xy-plane bounded by y = sin( x/2) and y = x for 0 x 1. What is the volume of the closed region in R3 obtained by revolving S about the x-axis?

A. 2 ...

#### Solution Summary

The volume of a solid of revolution is found.

$2.19