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    Integrals : Volume of Solid of Revolution

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    26. Let S be the closed region in the first quadrant of the xy-plane bounded by y = sin(pi x/2) and y = x for 0 ≤ x ≤ 1. What is the volume of the closed region in R3 obtained by revolving S about the x-axis?
    A. 2 - (pi /2) B. pi /6 C. pi /3
    D. pi /2 E. (2pi )/3

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    https://brainmass.com/math/integrals/integrals-volume-solid-revolution-33176

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    26. Let S be the closed region in the first quadrant of the xy-plane bounded by y = sin( x/2) and y = x for 0  x  1. What is the volume of the closed region in R3 obtained by revolving S about the x-axis?
    A. 2 ...

    Solution Summary

    The volume of a solid of revolution is found.

    $2.19

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