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    Indefinite Integral

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    Find the indefinite integral (3-x)/sq root of 9-x^2 dx(dx would be in the numerator). I tried to split this problem apart. First part was: The integral of 3/sq root of 9-x^2 dx and found 3 arcsin x/3 + C, then Second part was: The integral of -x/sq root of 9-x^2 dx and found -3/4 -x + C. I then put them back together to get 3 arcsin x/3 - 3/4 -x + C. Does this sound right?

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    Solution Summary

    An Indefinite Integral for a square root function is found.