Problem: The region R is bounded by the graphs of x - 2y = 3 and x = y2. Find the integral that gives the volume of the solid obtained by rotating R around the line x = -1.
I'm having a hard time setting up the integral, I think that I have the concept for finding the area of a 2d object using an integral but can't figure out how to take the next step to find volume or how line applies.
Here's what I have so far:
keywords: integration, integrates, integrals, integrating, double, triple, multiple
Please see the attached file for the fully formatted problems.
Find thevolume of thesolid formed by revolving the region bounded by y=x^3, x=2, and y=1 about the y-axis.
keywords: integrals, integration, integrate, integrated, integrating, double, triple, multiple
Using the shell method, find thevolume of a solid generated by revolving about the y axis.
The boundaries of thesolid are:
the line x=3
Note: I received a solution to this problem from an OTA, but it appeared that the integration wasn't complete. I would like to see another OTA sol
What is thevolume of thesolid of revolution obtained by rotating the region bounded by y = 1 and y = 5 - x^2 around the X-axis.
Find thevolume of thesolid of revolution obtained by rotating the region bounded by y = 1 and y = Tan x about the x-axis from x = 0 to x = pi/4.
See attached file
Use the disk method to find thevolume of thesolid of revolution formed by revolving the region about the x-axis.
Y = sqrt16-x
Solid region is a semi circle from 0,4 to 16,0 find thesolid amount between 5,0 and 6,0.